If both parents have the genotype Ee, what is the probability of their child having one eye?

To determine the probability of a child having one eye when both parents have the genotype Ee, it's essential to understand the traits represented by these alleles. In this scenario, "E" might denote a dominant trait, while "e" represents a recessive trait.

Using a Punnett square to visualize the possible genetic combinations is helpful. When both parents have the genotype Ee, the potential combinations of alleles for their offspring can be arranged as follows:

1. EE (homozygous dominant)

2. Ee (heterozygous)

3. eE (heterozygous, which is essentially also Ee)

4. ee (homozygous recessive)

When calculating the probabilities, the results show that there are four possible genotype outcomes in total. Out of these:

• Two outcomes (EE, Ee/eE) express the dominant trait.

• One outcome (ee) expresses the recessive trait.

Since the original question refers to the trait of having one eye, interpreting the genotypes involved means that two out of the four combinations result in the dominant expression. This leads to:

• Probability of dominant trait (expressed by either EE or Ee/eE): 75%

• Probability of recessive trait (ee):